Properties of Rhombus
A shape has four sides in which all the sides are same or identical. Every two opposite sides makes a parallel combination and the angles are also same. Rhombus has the properties of both equilateral and quadrilateral. Equilateral has a property of all sides are equal and the quadrilateral has a property of four sides.
Properties of rhombus:
Properties of rhombus:
A Rhombus Properties has four equal sides.
Diagonal:
Diagonals are the lines to be drawn to bisect the rhombus in which they are perpendicular. Diagonals of the rhombus make an angle of 90^0.
Area of a Rhombus:
Area: `1/2` (diagonal 1 + diagonal 2)
Perimeter:
Perimeter = side + side + side +side =4 sides.
Example problems for rhombus properties:
Example: 1
Find out the area of the given rhombus,if the length of diagonals is 25 cm and 17 cm
Solution:
Given,
Diagonal 1=25cm and diagonal 2=17cm.
Area of the rhombus = `1/2` (diagonal 1+diagonal 2) square unit.
= `1/2` (25 cm +17 cm)
= `42/2` cm2
= 21 cm2
Area of the given rhombus = 21 cm2
Example: 2
Find out the perimeter of the given rhombus, having a length of the one side is 14 m.
Solution:
Perimeter of the rhombus= 4side units
Given, side= 14 m
Perimeter of the rhombus= 4(14) m or 14 m+14 m+14 m+14 m
= 56 m
The Perimeter of the rhombus = 56 m.
Example problems for rhombus properties:
Example: 3
Determine the side of the rhombus whose perimeter value is 160 cm.
Solution:
Given, perimeter = 160 cm
We know, 4 sides =160 cm
Side=`160 /4` = 40 cm
A side of a given rhombus is 40 cm.
Example: 4
One diagonal of the given rhombus is 7 m and the area of that rhombus is 105 m2. Fine out the other diagonal of the rhombus.
Solution:
Given,
Diagonal 1=7 m
Area=105 m2
Area=`1/2` (Diagonal 1+ Diagonal 2)
105 = `1/2` ( 7 +d2)
7 + d2= 105`xx` 2
7+d2=210
d2=`210/7`
d2=30 m
The diagonal of the given rhombus is 30 m.
- Rhombus has a net angle of 360^0.
- Diagonal
- Area
- Perimeter
Diagonal:
Diagonals are the lines to be drawn to bisect the rhombus in which they are perpendicular. Diagonals of the rhombus make an angle of 90^0.
Area of a Rhombus:
Area: `1/2` (diagonal 1 + diagonal 2)
Perimeter:
Perimeter = side + side + side +side =4 sides.
Example problems for rhombus properties:
Example: 1
Find out the area of the given rhombus,if the length of diagonals is 25 cm and 17 cm
Solution:
Given,
Diagonal 1=25cm and diagonal 2=17cm.
Area of the rhombus = `1/2` (diagonal 1+diagonal 2) square unit.
= `1/2` (25 cm +17 cm)
= `42/2` cm2
= 21 cm2
Area of the given rhombus = 21 cm2
Example: 2
Find out the perimeter of the given rhombus, having a length of the one side is 14 m.
Solution:
Perimeter of the rhombus= 4side units
Given, side= 14 m
Perimeter of the rhombus= 4(14) m or 14 m+14 m+14 m+14 m
= 56 m
The Perimeter of the rhombus = 56 m.
Example problems for rhombus properties:
Example: 3
Determine the side of the rhombus whose perimeter value is 160 cm.
Solution:
Given, perimeter = 160 cm
We know, 4 sides =160 cm
Side=`160 /4` = 40 cm
A side of a given rhombus is 40 cm.
Example: 4
One diagonal of the given rhombus is 7 m and the area of that rhombus is 105 m2. Fine out the other diagonal of the rhombus.
Solution:
Given,
Diagonal 1=7 m
Area=105 m2
Area=`1/2` (Diagonal 1+ Diagonal 2)
105 = `1/2` ( 7 +d2)
7 + d2= 105`xx` 2
7+d2=210
d2=`210/7`
d2=30 m
The diagonal of the given rhombus is 30 m.